Monday, 8 April 2013

EMPLOYEE DATABASE SYSTEM IN SQL


i.Display the employee table with the list of fields namely employee number,name,dob,sex,job,grade,hire date,salary and department number to be referred as foreign key
SQL>create table employee(eno int, ename varchar2(20),dob varchar2(10),sex varchar2(10),job varchar2(20),grade varchar2(10),hiredate varchar2(20),salary varchar2(10),department varchar2(20),foreign key(Salary),foreign key(department));
Table created.
SQL> insert into employee values('&eno','&ename','&dob','&sex','&grade', '&hiredate', '&salary', '&department');
Enter value for eno: 1
Enter value for ename:stefin
Enter value for dob: 2/2/88
Enter value for sex: male
Enter value for hiredate: 1/2/12
Enter value for salary: 45000
Enter value for department: programmer
1 row created.

ii.Display the department table with the list of attributes namely department number and department name where department number as primary key
SQL>create table dept(deptno number(5),depname varchar2(20) primary key(deptno));
Table created.
SQL> insert into dept values('&deptno','&depname');
Enter value for depno: 1
Enter value for depname:stefin
1 row created.




iii.Write a correlated nested query to display the employee name and department number from employee table and department table.

SQL>select  ename,deptno from  employee,dept where eno in (select  deptno from deptno where deptno>1);

ENAME    DEPTNO
-----------    ------------
2                  mac
3                  hendry

iv.Write a query to display the employees earning more than the average salary in their own department.

SQL>select ename from employee where salary > (select avg(salary) from employee);

ENAME
-----------
stefin
Mac
v. Write a query to display the details of the employee whose department number is 20.
SQL>select  * from dept where deptno=20;
DEPTNO    DEPTNAME
------------   ----------------
20                  Design

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