SQL> create table customer(cid
int,cname varchar2(20),age int,sex varchar2(10),dob varchar2(20),address
varchar2(20),phno int,email varchar2(20),anualincome varchar2(10),primary
key(cid));
Table created.
SQL>
insert into customer values('&cid','&cname','&age','&sex','&dob','&address','&phno','&email','
&annualincome');
Enter value for cid: 1
Enter value for cname: john
Enter value for age: 58
Enter value for sex: male
Enter value for dob: 5/7/55
Enter value for address: german
Enter value for phno: 8548547895
Enter value for email: john2@gmail.com
Enter value for annualincome: 15000
1 row created.
SQL> select * from customer;
CID
CNAME AGE SEX
DOB ADDRESS PHNO EMAIL ANUALINCOME
---------- --------------------
---------- ----------
-------------------- -------------------- ---------- -----------------
1
john 58 male
5/7/55 german 8548547895 john2@gmail.com 15000
2 mac 47
male 1/9/65 japan
8547694858 mac33@gmail.com 14000
3 sam 21 male
1/7/91 greek 7894562158 sam2@yahoo.com 10000
SQL>select * from customer cid in
(select cid from customer where annualincome>10000);
CID
CNAME AGE SEX
DOB ADDRESS PHNO EMAIL ANUALINCOME
---------- --------------------
---------- ----------
-------------------- -------------------- ---------- -----------------
1 john 58 male
5/7/55 german 8548547895 john2@gmail.com 15000
2 mac 47 male
1/9/65 japan 8547694858 mac33@gmail.com 14000
SQL>select * from customer cid not in
(select cid from customer where anualincome>10000);
CID
CNAME AGE SEX
DOB ADDRESS PHNO EMAIL ANNUALINCOME
---------- --------------------
---------- ----------
-------------------- -------------------- ---------- -----------------
3 sam 21 male
1/7/91 greek 789456215 sam2@yahoo.com 10000
No comments:
Post a Comment